Math, asked by js1425543, 4 months ago

if 3a-2b+c=0 then the value of 9a^2-4b^2+c^2+6ac​

Answers

Answered by poulamisiddha
2

Answer:

2b(3a+2c)

Step-by-step explanation:

0 = 9a^2-4b^2+c^2+-6ab-4bc+6ac

So,

9a^2-4b^2+c^2+6ac = 2b(3a+2c)

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