If 3A + 4 B equal to 16 and AB equal to 4 find the value of 9 a square + 16 b square
Answers
Answer:
160
Step-by-step explanation:
3A+4B = 16
seq. both side
Given,
(3a+4b) = 16
ab = 4
To find,
The value of (9a²+16b²).
Solution,
The value of (9a²+16b²) will be 160.
We can easily solve this problem by following the given steps.
According to the question,
(3a+4b) = 16
Squaring on both sides,
(3a+4b)² = (16)²
Using the identity (a+b)² = a²+b²+2ab to expand the expression,
(Note that in this case a = 3a and b = 4b.)
(3a)²+(4b)²+2(3a)(4b) = 256
9a²+16b²+24ab = 256
We have to find the value of (9a²+16b²). So, moving 24ab from the left-hand side to the right-hand side will result in the change of the sign from plus to minus.
(9a²+16b²) = 256-24ab
Putting the value of ab,
(9a²+16b²) = 256-24(4)
(9a²+16b²) = 256-96
(9a²+16b²) = 160
Hence, the value of (9a²+16b²) is 160.