Question

if (3a+4b) = 16 and ab = 4, find the value of (9a^2+16b^2)

Answer 1

$\textbf{ \large{ Hello Mate! }}$

$3a + 4b = 16 \\ \\ on \: squaring \: both \: sides \\ \\ {(3a + 4b)}^{2} = {16}^{2} \\ 9 {a}^{2} + 16 {b}^{2} + 2(3a)(4b) = 256 \\ 9 {a}^{2} + 16 {b}^{2} + 24(4) = 256 \\ \\ 9{a}^{2} + 16 {b}^{2} = 256 - 96 \\ 9{a}^{2} + 16 {b}^{2} = 160$

Answer 2

Answer:

Answer is 160

Step-by-step explanation:

Thank you so much for the answer it helped me