Question

If (3a+4b)=16 and ab=4,find the value of (9a square +16b square)

Answer 1

Answer:

3a+4b=16

onsquaringbothsides

(3a+4b)

2

=16

2

9a

2

+16b

2

+2(3a)(4b)=256

9a

2

+16b

2

+24(4)=256

9a

2

+16b

2

=256−96

9a

2

+16b

2

=160

Answer 2

(3a+4b)²=9a²+16b²+2(3a)(4b)

16²=9a²+16b²+24(4) ......ab=4

256=9a²+16b²+96

256-96=9a²+16b²

160=9a²+16b²

please mark as brainliest