If 3a=4b=6c a+b+c=27√29 find (a^2+b^2+c^2)^(1/2)
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Given:
3A=4B=6C
a+b+c= 27√29
We have to find
√(a²+b²+c²)
_____________________________
The value of √(a²+b²+c²)= 87
_____________________________
Hope this will help you...
3A=4B=6C
a+b+c= 27√29
We have to find
√(a²+b²+c²)
_____________________________
The value of √(a²+b²+c²)= 87
_____________________________
Hope this will help you...
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