if 3a=4b=6c and a+b+c=27root29 then,root a2+b2+c2 is __________
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b=3a/4 and c=a/2
then a+b+c=27√29
a(1+3/4+1/2)=27√29
a(9/4)=27√29
a=12√29 a²=144x29
b=9√29 b²=81x29
c=6√29 c²=36x 29
then √(a²+b²+c²)= √29(144+81+36) =√29(261)
then a+b+c=27√29
a(1+3/4+1/2)=27√29
a(9/4)=27√29
a=12√29 a²=144x29
b=9√29 b²=81x29
c=6√29 c²=36x 29
then √(a²+b²+c²)= √29(144+81+36) =√29(261)
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