Question

if 3a=4b and a+b=7√29 find √a^2+b^2

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Answer 1

Step-by-step explanation:

Given,

3a=4b

that implies,

a = 4b /3

given,

a+b = 7√29

that implies,

4b/3 + b = 7√29

4b+3b = 3(7√29)

7b = 21√29

b= 3√29

b²= 9×29

= 261

a= 4b/3

= (12√29) /3

= 4√29

a² = 16×29

to find,

√(a²+ b²)

=√ (29×16 + 29×9)

=√(29)(16+9)

=5√29

Answer 2

Answer:

√a²+b² =√(29*25)=5√29

Step-by-step explanation:

3a=4b so a/b=4/3

b=(3/4)a

a+b=7√29

a+(3/4)a=7√29

7a/4 =7√29

a=4√29

so b=7√29-4√29

b=3√29

a²+b² = (4√29)²+(3√29)²=29(16+9)=29*25

√a²+b² =√(29*25)=5√29