If 3a+4b3c+4d = 3a-4b3c-4d, then
A) ab = cd B) ad = bc C) ac = bd D) a = b = c ≠ d
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Correct answer is B)
Given 3a + 4b/3c + 4d = 3a – 4b/3c – 4d
App. Alternedo = 3a + 4b/3a – 4b = 3c + 4d/3c – 4d
App. Componendo and dividend
3a + 4b + 3a – 4b/3a + 4b – 3a + 4b = 3c + 4d + 3c – 4d/3c + 4d – 3c + 4d
∴ 6a/8b = 6c/8d
Or a/b = c/d
Hence proved
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