if 3a= b+c then cotB/2 .cotC/2=
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Answer: the correct is 2
Step-by-step explanation:
Given that: 3a=b+c
cot A\2*cotB\2 =√[s(s-b)\(s-a)(s-c)]*
√[s(s-c)\(s-b)(s-a)=
s\s-a = 2a\2a-a = 2a\a = 2
Hence it is the correct answer
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