Question

If 3a +t, 2a + 9 and a + 13 are consecutive terms in AP.
Find the value of t.​

Answer 1

Step-by-step explanation:

answer and explanation given in picture

please mark my answer as bralinlist and follow me thanks you

Answer 2

$\bold\red{\underline{\underline{Answer:}}}$

$\bold{The \ value \ of \ t \ is \ 5.}$

$\bold\blue{Explanation}$

In an A.P. common difference (d) is constant.

$\bold\orange{Given:}$

Consecutive terms of an A.P. are

3a+t, 2a+9 and a+13.

$\bold\pink{To \ find:}$

Value of t.

$\bold\green{\underline{\underline{Solution}}}$

In the given A.P.

t1=3a+t, t2=2a+9 and t3=a+13

Common difference will be always constant in an A.P.

Therefore,

t2-t1=t3-t2

2a+9-(3a+t)=a+13-(2a+9)

2a+9-3a-t=a+13-2a-9

-a+9-t=-a+4

t=9-4

t=5

Therefore,

$\bold\purple{The \ value \ of \ t \ is \ 5.}$