Question

if 3a²-8a-3=0, find the value of a-1/a and a+1/a​

Answer 1

Answer:

3a² - 8a - 3 = 0

3a² - 9a + a - 3 = 0

3a(a - 3) + 1(a - 3) = 0

(3a + 1)( a - 3) = 0

3a + 1 = 0      ; a - 3 = 0

3a = -1          ; a = 3

a = -1/3        ; a = 3

Negative value will not be accepted. So, a = 3

Now.

a - 1/a        

Put a = 3

= 3 - 1/3

=   (9-1)/3

= 8/3

if it's (a - 1)/a

then.

(3 - 1)/3  

= 2/3

Now.

a + 1/a

put  a = 3

3 + 1/3

= (9 + 1)/3

= 10/3

if it's (a + 1)/a then

(3 + 1)/3

= 4/3