Question

if -3and 2 are roots of quadratic equation x^2-(p+2)x-q=0 then the values of p and q are​

Answer 1

Answer:

(-3)^2-(P+2)-3-Q=0

9+3P+6-Q=0

15+3p-q=0

3p-q=15-----------------(1)

2^2-(p+2)2-q=0

4-2p-4-q=0

-2p-q=0-----------------(2)

solving 1 and 2

eliminating q, we get 5p=15, p=3

substituting p=3 in 2, we get q=-6