Question

if 3and-3are two zeros of the polynomial (x4+x3-11x-9x+18), find all the zeros of the given polynomial
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Answer 1

Answer:

-2,1

Step-by-step explanation:

(x-3)(x+3)=0  

x2+3x-3x+9=0

x2+9=0

so to divide x4+x3-11x2-9x+18 we have to divide both the zeroes.

now divide x4+x3-11x2-9x+18 by x2+9

quotient would come x2+x-2

now we find roots of x2+X-2 which will be the roots of x4+x3-11x2+18 as we;;

x2+x-2=0

x2+2x-x-2=0

x(x+2)-1(x+2)=0

(x+2)(x-1)=0

x=-2,1

hence remaining zeros are -2 and 1