Question

if 3@5=49, 2@3=19, 9@10=271 then 6@7=?​

Answer 1

Answer:

127

Step-by-step explanation:

3@5=49=3x3+5x5+3x5,

2@3=19=2x2+3x3+2x3,

9@10=271=9x9+10x10+9x10

Therefore, 6@7=6x6+7x7+6x7=127

Answer 2

Given :- if 3@5=49, 2@3=19, 9@10=271 then 6@7=?

Solution :-

Logic :- a @ b = a² + b² + ab

Explanation :-

3 @ 5

→ 3² + 5² + 3 * 5

→ 9 + 25 + 15

→ 49

similarly,

2 @ 3

→ 2² + 3² + 2 * 3

→ 4 + 9 + 6

→ 19

similarly,

9 @ 10

→ 9² + 10² + 9 * 10

→ 81 + 100 + 90

→ 271

therefore, applying same logic in next,

6 @ 7

→ 6² + 7² + 6 * 7

→ 36 + 49 + 42

→ 127 (Ans.)

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