Question

If 3cosθ=1, find the value of 6sin²θ+tan²θ/4cos²θ

Answer 1

Answer:

10/3

Step-by-step explanation:

Mark me as a brainlist and follow also

Answer 2

Answer:

30

Step-by-step explanation:

Given :

3 cos Ф = 1

Diving by 3 both side we get :

3 / 3 cos Ф = 1 / 3

cos Ф = 1 / 3

We know :cos Ф = B / H

Also :

H² = P² + B²

P = √ ( H² - B² )

P = √ 9 - 1

P = 2 √ 2

Now :

6 sin² Ф + tan² Ф / 4 cos² Ф

6 ( P / H )² + ( P / B )² / 4 ( B / H )²

( 6 × 8 / 9 + 8 / 1 ) / 4 × 1 / 9

= > ( 48 / 9 + 8 ) / 4 / 9

= > [ ( 48 + 72 ) / 9 ] / ( 4 / 9 )

= > 120 / 4

= > 30

Therefore , the value of 6 sin² Ф + tan² Ф / 4 cos² Ф is 30.