Question

if 3cosα-4sinα=5 so prove that 3sinα+4cosα=0
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Answer 1

Answer:

Step-by-step explanation:

3cosa-4sina=5

3cosa-4cosa=5

-1cosa=5

Cosa= -5

Similarly, 3cosa-4sina=5

3sina-4sina=5

-1sina=5

Sina= -5

Now, 3sina+4cosa =0