If 3cos theta-4sin theta=2cos theta+sin theta, find tan theta
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3cosA-4sinA=2cosA+sinA
3cosA-2cosA=sinA+4sinA
cosA=5sinA
1=5sinA/cosA
1/5=sinA/cosA
1/5=tanA
Hence tanA=1/5
3cosA-2cosA=sinA+4sinA
cosA=5sinA
1=5sinA/cosA
1/5=sinA/cosA
1/5=tanA
Hence tanA=1/5
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