Question

If 3cos² theta=9/4,then theta=​

Answer 1

Step-by-step explanation:

$3 { \cos}^{2} \theta = \frac{9}{4} \\ { \cos}^{2} \theta = \frac{3}{4} \\ \cos( \theta) = ± \frac{ \sqrt{3} }{2} \\ \theta = \frac{\pi}{6} + 2n\pi \: \: \: or \: \: \: - \frac{\pi}{6} + 2n\pi \: in \: rad \\ where \: \: n \: \: is \: an \: integer \\ or \\ {30}^{o} + {360}^{o} n \: \: \: or \: \: \: - {30}^{o} + {360}^{o} n$

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