Question

If 3cosA - 4sinA =0 , Evaluate that SinA+2CosA / 3cosA -Sin A

Answer 1

Answer: 11/9

Step-by-step explanation:

   3cosA - 4sinA = 0

⇒ 3cosA = 4sinA

⇒ sinA/cosA = 3/4

⇒ tan = 3/4

∴ (sinA + 2cosA) ÷ (3cosA - sinA)

 By dividing each term by cosA we get,

 (tanA + 2) ÷ (3 - tanA)

= (3/4 + 2) ÷ (3 - 3/4)

=  11/4 ÷ 9/4

= 11/9

Answer 2

Answer:

11/9

Step-by-step explanation:

3cos A - 4sin A =0

3cos A = 4 Sin A

sin a/cos a = 3/4

tan a = 3/4

(sin A+ 2cos A) ÷ (3cos A. - sin A)

by dividing each term by cos A we get

(tan A + 2)÷ (3-tan A)

(3/4+2)÷(3-3/4)

11/4÷9/4

= 11/9

I hope this is helpful for you