Question

if 3cos@-4sin@=5 ...then prove that 3sin@+4cos@=0​

Answer 1

Heya mate,

Go foreward for ur ans,

Given

➪3cosα + 4sinα = 5

➪4sinα = 5 - 3cosα

Square (1), yields

➪16sin²θ=25−30cosθ+9cos²θ.

Use identity sin2θ=1−cos2θ and substitute to (2)

➪16(1−cos²θ) =25−30cosθ+9cos²θ

➪25cos²θ−30cosθ+9 =0

➪ (5cosθ−3)²=0

Therefore

$cos \alpha = \frac{3}{5}$

Isse sin theta aa jaayega 4/5

To find

➪3sinθ - 4 cosθ

$3 \times \frac{4}{5} - 4 \times \frac{3}{5} \\ \\ \frac{12}{5} - \frac{12}{5}$

➪ 0

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If 3sin (theta) +4 cos (theta) =5 then find the value of 4 sin (theta) - 3 cos theta, also find sin theta and cos theta

f 3sin (theta) +4 cos (theta) =5 then find the value of 4 sin (theta) - 3 cos theta, also find sin theta and cos theta https://brainly.in/question/5450852?utm_source=android&utm_medium=share&utm_campaign=question

Answer 2

Answer:

3 sin teta + 4 cos teta = 5

squaring on both sides