Question

if 3cosmø=2then find the value of 4sinø - 3cosø/2sinø+6cos ø​

Answer 1

Step-by-step explanation:

Given,

3cotθ=2

cotθ=32

tanθ=23

2sinθ+6cosθ4sinθ−3cosθ

=2sinθ+6cosθ4sinθ−3cosθ×sinθsinθ ---------- ( Multiply and divide by sinθ )

=sinθ2sinθ+6cosθsinθ4sinθ−3cosθ

=2+6(sinθcosθ)4−3(sinθcosθ)

=2+6cotθ4−3cotθ

=2+6×3\2/ 4−3×3\2

=2+4/4−2

=6/2

=3/1