Question

If 3cot theta=4,then find the value of 4cos theta-sin theta/2cos theta+sin theta

Answer 1

Answer:

First find the hypotenuse

(hy)*2=(p)*2+(b)*2

(hy)*2=(3)*2+(4)*2

(hy)*2=9+16

(hy)*2=25

(Hy)=5

Now,

4(cos theta - sin theta)/2(cos theta + sin theta)

4(4/5-3/5)/2(4/5+(3/5))

(16/5)-(3/5))/(8/5)+(3/5)

(13/5)/(11/5)

13/11 ans.

Step-by-step explanation:

Answer 2

Answer:

3 cot theta =4

cot theta = 4/3

h2 = p2+b2

h = 5

4cos theta - sin theta / 2cos theta + sin theta

=> 4×4/5 -3/5 /2×4/5+3/5

=> 16/5 - 3/5 / 8/5 +3/5

=> 13/5 /11/5

=> 13/11

I hope it will be helpful for you.

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