If 3cot thita=4 then (5sin thita+ 3 cos thita)/(5 sin thita- 3 cos thita)=?
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hey 1st i am just keeping thita as A ok becoz i can't write every time thita in the following
we know that 3 cotA = 4
so cot A = 4/3 (just i send the 3 to this side so its dividing )
so in right triangle cotA = adj/opp
so by pythagoras theorem hyp = 5 ok
now sinA = opp/hyp =3/5
similarly cosA = adj/hyp = 4/5
so now u must keep values in the give equation
i can't write but i will tell u the answer
the final answer is = 9
we know that 3 cotA = 4
so cot A = 4/3 (just i send the 3 to this side so its dividing )
so in right triangle cotA = adj/opp
so by pythagoras theorem hyp = 5 ok
now sinA = opp/hyp =3/5
similarly cosA = adj/hyp = 4/5
so now u must keep values in the give equation
i can't write but i will tell u the answer
the final answer is = 9
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