If 3cotA =2 then find the value of
4sin A-3cos A by 2sin A+ 3cos A
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2
Answer:
0.5
Explanation:
3cot A=2
cot A=2÷3
tan A=3÷2 ( because cot A=1÷tan A)
sin A÷cos A=3÷2 ( because tanA=sin A÷cos A)
since;
since;From above equation,
sin A=3 and cos A=2
Now putting the value of sinA and cosA in the given equation in the question:
= 4×3-3×2
2×3+3×2
= 12-6
6+6
= 6
12
= 1
2
= 0.5 Ans..
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