If 3cota=4,cheak weather 1-tan²a
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3 cot a = 4 then
cot a = 4/3
cot a = base/hypotenuse
hypotenuse^2= (4^2)+(3^2)
hypotenuse=✓16+9
hypotenuse=✓25
hypotenuse = 5
1-(3/4)^2
1-9/16
16-9/16
7/16
1-tan^2 a= 7/16
cot a = 4/3
cot a = base/hypotenuse
hypotenuse^2= (4^2)+(3^2)
hypotenuse=✓16+9
hypotenuse=✓25
hypotenuse = 5
1-(3/4)^2
1-9/16
16-9/16
7/16
1-tan^2 a= 7/16
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