Question

If 3Cote = 2 then find the value (4Sin - 3 Cos )/(2 Sin e + 6 Cos e)​

Answer 1

Answer:

$cotx = \frac{2}{3} \\ now \: \frac{4sinx \: - 3cosx}{2sinx \: + 6cosx} \\ = \frac{sinx(4 - 3cotx)}{sinx(2 + 6cotx)} \\ = \frac{4 - 3 \times \frac{2}{3} }{2 + 6 \times \frac{2}{3} } \\ = \frac{4 - 2}{2 + 4} \\ = \frac{2}{6} \\ = \frac{1}{3}$

Answer 2

Answer:

this is correct...............................