Question

if 3cottheeta=4 then find 9[5sin-3cos]/5sin +3cos

Answer 1

Answer:1

Step-by-step explanation:

3cot theeta =4

=Cot theeta =4/3

=Cos theeta/sin theeta=4/3 =cos theeta=4, sin theeta=3

9(5sin-3cos)/5sin +3cos

=9(5×3-3×4)/5×3+3×4

=9(15-12)/15+12

=9×3/27

=27/27

=1

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