Physics, asked by khushi638873, 11 months ago

If (3i^-2j^+2k^).(2i^-xj^+3k^)=-12, then find the value of x​

Answers

Answered by pari1918
14

Explanation:

(3i^-2j^+2k^)(2i^-xj^+3k^)=-12

6+2x+6=-12

12+2x=-12

2x=-12-12

2x=-24

x=-24/2

x=-12

Answered by krishna210398
2

Answer:

Vector algebra

Explanation:

(3i^-2j^+2k^)(2i^-xj^+3k^)=-12

6+2x+6=-12

12+2x=-12

2x=-12-12

2x=-24

x=-24/2

x=-12

an algebra for which the elements involved may represent vectors and the assumptions and rules are based on the behavior of vectors.

the formula to decide the magnitude of a vector (in  dimensional space) v = (x, y) is: |v| =√(x2 + y2). This system is derived from the Pythagorean theorem. the method to determine the magnitude of a vector (in three dimensional area) V = (x, y, z) is: |V| = √(x2 + y2 + z2)

Vector algebra is beneficial to discover the issue of the force in a selected path. Vector algebra is used to discover the interplay of two or more quantities in physics. Scalar triple made from vectors is the dot of one vector with the pass product of the alternative  vectors. In linear algebra, scalars are typically real numbers.

Vectors - A vector is an detail in a vector space. it is a quantity that can describe each the route and magnitude of an detail. Vector area - The vector area includes vectors that can be delivered collectively and multiplied by way of scalars.

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