if | 3i+2j+ak|=5, then a=
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Just as a note, you mean the value of “a”, not the value of “A.” A is given as a fixed vector.
Vectors that are perpendicular to one another have zero inner product:
A . B = 5*2 + 7*2 + 3*a = 0
Note that the last operator is + because both vectors have negative k components; the product of two negatives is a positive.
This is easy to solve:
10 + 14 + 3a = 0
3a = -24
a = -8.
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