Question

if 3j-(k+5)=16-4K, what is the value of j+k?

Answer 1

Step-by-step explanation:

Simplifying 3j + -1(k + 5) = 16 + -4k Reorder the terms: 3j + -1(5 + k) = 16 + -4k 3j + (5 * -1 + k * -1) = 16 + -4k 3j + (-5 + -1k) = 16 + -4k Reorder the terms: -5 + 3j + -1k = 16 + -4k Solving -5 + 3j + -1k = 16 + -4k Solving for variable 'j'. Move all terms containing j to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 3j + 5 + -1k = 16 + 5 + -4k Reorder the terms: -5 + 5 + 3j + -1k = 16 + 5 + -4k Combine like terms: -5 + 5 = 0 0 + 3j + -1k = 16 + 5 + -4k 3j + -1k = 16 + 5 + -4k Combine like terms: 16 + 5 = 21 3j + -1k = 21 + -4k Add 'k' to each side of the equation. 3j + -1k + k = 21 + -4k + k Combine like terms: -1k + k = 0 3j + 0 = 21 + -4k + k 3j = 21 + -4k + k Combine like terms: -4k + k = -3k 3j = 21 + -3k Divide each side by '3'. j = 7 + -1k Simplifying j = 7 + -1k

Answer 2

Answer:

7

Step-by-step explanation:

3j-k-5=16-4k

3j-k+4k=16+5

3j+3k=21

3(j+k)=21

j+k=21/3

j+k=7