Math, asked by MODIJIPM, 2 days ago

If 3k - 2 , 4k - 6 and k + 2 are three consecutive terms of A.P., then find the value of K

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Answered by suhail2070

Step-by-step explanation:

$3k - 2 \: \: \: \: \: \: \: 4k - 6 \: \: \: \: \: \: \: \: k + 2 \\common \: difference \: is \: same \\ (4k - 6) - (3k - 2) = (k + 2) - (4k - 6) \\ \\ k - 4= - 3k + 8 \\ \\ 4k = 12 \\ \\ k = 3.$

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If 3k - 2 , 4k - 6 and k + 2 are three consecutive terms of A.P., then find the value of K​

Answers

If 3k - 2 , 4k - 6 and k + 2 are three consecutive terms of A.P., then find the value of K