Question

if 3k-2, 4k - 6 and k+2 are three consecutive terms of an AP. then find the value of k?​

Answer 1

Step-by-step explanation:

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Answer 2

ANSWER

It is given that k+2,4k−6,3k−2 are the consecutive terms of A.P, therefore, by arithmetic mean property we have, first term+third term is equal to twice of second term that is:

(k+2)+(3k−2)=2(4k−6)⇒

4k=8k−12

⇒4k−8k=−12

⇒−4k=−12

⇒4k=12

k=4/12=3

Hence k=3.