Question

If 3k-2,4k-6,k+2 are three consecutive terms of A.P ., then find the value of k.

Answer 1

Step-by-step explanation:

-2,4k-6,k+2 are three consecutive

Answer 2

Answer:

The value of k is 4.

Given:

• 3k - 2, 4k - 6 and k + 2 are the three consecutive terms of an A.P.

To find:

• The value of k.

Solution:

Here,

$\sf{t_{1}}$ = 3k - 2,

$\sf{t_{2}}$ = 4k - 6,

$\sf{t_{3}}$ = k + 2

$\boxed{\sf{2\times \ t_{2}=t_{1}+t_{3}}}$

$\sf{\therefore}$ 2 (4k - 6) = (3k - 2) + (k + 2)

$\sf{\therefore}$ 8k - 16 = 4k

$\sf{\therefore}$ 4k = 16

$\sf{\therefore}$ k = 16/4

$\sf{\therefore}$ k = 4

The value of k is 4.