if (3k,4k-1) is a solution of the linear equation X+y=6, find the value of k
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Answer:
x + y = 6
3k + 4k - 1 = 6
7k - 1 = 6
7k = 6 + 1
7k = 7
k = 1
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Given : (3k,4k-1) is a solution of the linear equation x+y=6
To Find : Value of k
Solution:
linear equation x+y=6
point lies on line (3k,4k-1)
x = 3k
y = 4k-1
3k + 4k - 1 = 6
=> 7k = 7
=> k = 1
Value of k = 1
Point is 3k = 3
4k - 1 = 3
( 3 , 3) is a solution of x + y = 6
as 3 + 3 = 6
Value of k = 1
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