Question

if 3k-log1/2=54 then find the value of k​

Answer 1

Answer:

The value of k will be:

$k=\dfrac{54-log(2)}{3}.$

Step-by-step explanation:

Here the given function is:

$3k-log(\dfrac{1}{2})=54$

We know the formula of:

$log(\dfrac{a}{b})=log(a)-log(b)$.

Hence the above function can be written in this form:

$3k-[log(1)-log(2)]=54$

Value of:

$log(1)=0$.

Therefore it will become as:

$3k-[0-log(2)]=54\\3k+log(2)=54\\3k=54-log(2)\\k=\dfrac{54-log(2)}{3}$