Question

if = 3l=5 is a multipled of 3 where 2 that is digit what might be the value of z?
​

Answer 1

Answer:

Since 31z5 is a multiple of 3 ,the sum of its digits must be a multiple of 3 i.e. 3+1+z+5=9+z.

Hence 9+z is a multiple of 3

Since z is a single digit which can value from 0−9,

Possible values of z will be,

9+0=9

9+3=12

9+6=15

9+9=18

Thus, there can be four possible values i.e. 0,3,6 or 9