If 3log(x+1)=log 27 then find the value of x
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3log(x+1)=log27
3log(x+1)=log27
=>log(x+1)³=log27 [alogb=logb^a]
=>(x+1)³=27
=>(x+1)³=3³
=>x+1=3
=>x=2
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