Question

If (3m+1)x^2+2(m+1)x+m=0 has equal roots find m

Answer 1

Answer:

Given that the equation is,

(3m+1)x²+2(m+1)x+m=0

Since it has equal roots...

So, b²-4ac=0

4(m+1)²-4(3m+1)(m)=0

(m+1)²-(3m+1)m=0

m²+1+2m-3m²-m=0

-2m²+m+1=0

2m²-m-1=0

2m²-2m+m-1=0

2m(m-1)+1(m-1)=0

2m=-1, m=1

m=-1/2,m=1

Step-by-step explanation:

Hope it helps you frnd.....