If 3m – 5n = – 1 and 2m = n – 3, find the values of (3m + 5n) and (m + 2n).
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(3m-5n+0=-1)____×3. (1)
(2m-n+3=0)_____×2. (2)
6m-3n+9=0
6m-10n+0=-2
--. +. --. +
= 7n+9= 2
then solving this we get n= (-1)
and putting value of n in (2) equation
We get m = -2
then put value,
(3m+5n) = (3(-2) + 5(-1) )= -8
(m+2n). = (-2 +2 (-1) ) = -4
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