if 3nc2 = 2nc1 find n
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Answer:
Find n, if
2n
C
3
:
n
C
2
=52:3
n
C
2
2n
C
3
=
3
52
∴
2
n(n−1)
3×2×1
2n(2n−1)(2n−2)
=
3
52
∴
3×2×1×n(n−1)
2n(2n−1)2(n−1)
×2=
3
52
∴
3
4(2n−1)
=
3
52
∴4(2n−1)=52
∴2n−1=
4
52
∴2n−1=13
∴2n=13+1
∴2n=14
∴n=7
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