Question

if 3p + 2q = 10 and pq =12 then find 27p^3+8q^3

Answer 1

27p^3 + 8q^3
= (3p)^3 +( 2q)^3
= (3p+2q)^3
= 10^3. {Given 3p+2q=10}
= 1000

Answer 2

let 27p^3 +8q^3 is x
3p+2q=10 so 3p^2+2q^2=root 10
so now = 27p^3+8q^3 +3p^2+2q^2 + 3p×2q×2
= x + root 10 + 12
= x+12 root 10
= x= -12 root 10