Question

If 3p-4q=5 and pq=3 , then the value of 27p³−64q³ is

Answer 1

Step-by-step explanation:

3p-4q=5

(3p-4q)²=5²

9p²+16q²-24pq=25

9p²+16q²-24×3=25

9p²+16q²-72=25

9p²+16q²-72=259p²+16q²= 97

27p³-64q³

3p³-4q³

(3p-4q){(3q)²+(4q)²+3p×4q}

(3p-4q)(9q²+16q²+12pq).

(5)(97+12×3)

5(97+36)

5(133)

665

...........666.......