Question

If 3p-89 = 20 and p and q are integers, which of the following must be false?
1) if p is positive, q can be negative
2) if p is negative, q cannot be positive
3) there is a solution for q such that 197 sqs 203
41 there is a solution for p such that 197 pš 203
proved that. ​

Answer 1

Answer:

1) if p is positive, q can be negative

Step-by-step explanation:

Ist of all Its 3p-8q =20 not 30-89 ok then 1st of all solve the equation so you find the answer

just like

3p-8q=20

8q=20-3p

for

p=4 and q= -1