If 3p² = 5p +2 and 3q² = 5q +2
then the equation whose
roots 3p-2q and 39–2p is
O
x? – 5x +100 = 0
O
3x² – 5x –100 = 0
O
3x² + 5x +100 = 0
O
5x? – x + 7 = 0
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Answer:3x² - 5x - 100 = 0
Step-by-step explanation:
We are given that p and q are both roots of the quadratic
3x² - 5x - 2 = 0.
So p+q = 5/3 and pq = -2/3.
Let α=3p-2q and β=3q-2p. We need a quadratic with α and β as roots.
We have
α+β = (3p-2q) + (3q-2p) = p+q = 5/3
and
αβ = (3p-2q) (3q-2p)
= 9pq - 6p² - 6q² + 4pq
= 13pq - 6(p²+q²)
= 25pq - 6(p²+2pq+q²)
= 25pq - 6(p+q)²
= 25 × (-2/3) - 6 × (5/3)²
= - 50/3 - 50/3
= -100/3
So α and β are roots of
3x² - 5x - 100 = 0.
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