Question

if 3raised to X +64=2⁶+(√3)⁸, then the value of x is?
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Answer 1

${3}^{x} + {4}^{3} = {2}^{6} + { \sqrt{3} }^{8}$

${3}^{x} + ({ {2}^{2} )}^{3} = {2}^{6} + {( \sqrt{ {3}^{2} }) }^{4}$

${3}^{x} + {2}^{6} = {2}^{6} + {3}^{4}$

$x = 4$