If 3rd and 9th term of an A.P. are 4 and -8 respectively then which term of its will be zero?
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Answer:
given t3=4
=>a+2d=4 ------ 1
and t9=-8
=>a+8d=-8 -------2
on doing equations 1-2
we get -6d=12
d=12/-6=-2
on substitution of d in equation 1 we get
a=8
now
tn=0
a+(n-1)d=0
8+(n-1)*-2=0
(n-1)*-2=-8
(n-1)=-8/-2
(n-1)=4
n=5
so 5th term of ap is 0
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