Question

If 3rd and 9th term of ap are 19 and 41 respectively then find value of 30th term​

Answer 1

Answer:

Tñ =a+(n−1)d

Where a is the first term, d is the common difference and Tñ

denotes the n-th term of an AP.

Given:

19=a+5d

41=a+16d

Solving the above equations gives: d=2,a=9

Therefore, T

40

=9+39⋅2=

87

Answer 2

Answer:

let a be the first term and d be the common difference of an A.P

given a_{3}a

3

=19⇒a+2d=19

a_{9}a

9

=41⇒a+8d=41

by solving we get a=35/3 and d=11/3

a_{30}a

30

=a+29d=35/3+29(11/3)=354/3=118

Step-by-step explanation:

Pʟs ᴍᴀʀᴋ ᴀs ʙʀᴀɪɴʟɪᴀsᴛ ᴀɴᴅ ғᴏʟʟᴏᴡ ᴍᴇ✌️