Question

if 3rd and the 9th term of an ap are 4 nd -8 which term of ap is zero

Answer 1

a₃ = 4

a+2d = 4

a₉ = -8

a+8d = -8

a+2d = 4

(-) (-)    (-)  

    6d = -12

    d= -2

substitute d=-2

a+2d = 4

a+2(-2) = 4

a= 4+4 = 8

a = 8

a₂ = 8-2=6

a₃ = 6-2 = 4

a₄ = 4-2 = 2

a₅= 2-2=0

∴ a₅=0

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

It is given that 3rd and ninth term of AP are 4 and -8 respectively.

It means ᵃ₃=4 and a₉=−8 where, a₃ and a9 are third and ninth terms respectively.

Using formula an=a+(n−1)d,   to find nth term of arithmetic progression, we get

4 =  a + (3-1)d    And, -8 = a + (9-1)d

⇒4=a+2d   And, −8=a+8d

These are equations in two variables. Lets solve them using method of substitution.

Using equation 

4=a+2d,

we can say that 

a=4−2d.

Putting value of a in other equation 

−8=a+8d,

we get

−8=4−2d+8d

⇒−12=6d

⇒d=−126=−2

Putting value of d in equation  

−8=a+8d,

we get

−8=a+8(−2)

⇒−8=a−16

⇒a=8

Therefore, first term =a=8    and

Common Difference =d=−2

We want to know which term is equal to zero.

Using formula an=a+(n−1)d,   to find nth term of arithmetic progression, we get

0=8+(n−1)(−2)

⇒0=8−2n+2

⇒0=10−2n

⇒2n=10

⇒n=102=5

Therefore, 5th term is equal to 0.

I hope, this will help you.

Thank you______❤

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