If 3rd term, 6th term and last term of an ap is 6, 48 and 3072 respectively, find first term and no. Of terms
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Answer:
Step-by-step explanation: we have,
3rd term=> a+2d =6......(1)
4th term=> a +3d=48.......(2)
Last term=>an= 3072.......(3)
Now,
(2)-(1)=>d =42
So,(1)=>a=6-2d =6-2×42= -78
Now ,
(3)=>a+(n-1)d =3072 which is the reqd. No. of terms.
And the reqd ap is....a,a+d,....
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