if 3rd term of an AP is 9 and 9 term of same AP is 3 find 12 pls give answer fast
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a3 = a+2d = 9...............(I)
a9 = a+8d = 3................(ii)
on subtracting (I) from (ii) , we get
6d = -6
=> d = -1
putting value of d , we get
a -2 = 9
=> a = 11
a12 = a + 11d = 11 + 11 (-1) = 11-11 = 0
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